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-5x^2-50x=105
We move all terms to the left:
-5x^2-50x-(105)=0
a = -5; b = -50; c = -105;
Δ = b2-4ac
Δ = -502-4·(-5)·(-105)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-20}{2*-5}=\frac{30}{-10} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+20}{2*-5}=\frac{70}{-10} =-7 $
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